For this assignment you will practice creating, examining, and combining different data structures in R. This assignment is different from others in that it takes a worksheet format with built-in error checking. Each time you complete an answer, if you knit the document it should check your answer (but don’t remove “NULL” on an answer before you want it checked or you’ll get an error!) For this reason, you should re-knit every time you answer a question, so that if something goes wrong, you know the last edit caused the issue!
You will need to do the following:
#
); remove and replace the comments with
your code:# DO NOT EDIT
”;
these are used to test your code.>
) in designated locations to answer questions.
Example for Code Questions:
# Ex 1) Create a vector of the numbers 1, 5, 3, 2, 4.
example <- NULL
# You would write this:
example <- c(1,5,3,2,4)
# Ex 2) Add the number 10 to the sixth position of example2
example2 <- example
example2 <- NULL
# You would write:
example2[6] <- 10
Example for Text Questions: 1) “How do vectors differ from lists?”
A vector is a one dimensional object where every element is the same type of data. Lists are one dimensional but elements can be different data types.
# 1) Use "seq()" to create a vector of numbers from 0 to 45 in increments of 5
vec_num <- NULL
# 2) Use ":" to create an integer vector of the numbers 11 through 20.
vec_int <- NULL
# 3) "LETTERS" contains the 26 capital letters in order. Use "LETTERS" and "[ ]" to create a vector of the last 10 capital letters.
vec_cha <- NULL
# 4) "letters" contains the 26 lowercase letters in order. Use "factor", "letters", and "[ ]" to create a factor variable using the first ten lower case letters.
vec_fac <- NULL
# 5) Use "c()" to combine "vec_cha" and "vec_fac" into "vec_let". Do not convert it to a factor!
vec_let <- NULL
# 6) Use "c()" and "[ ]" to combine the first 4 elements of "vec_num" with the last
# 4 elements of "vec_int" to create "vec_ni".
vec_ni <- NULL
# 7) Use "rev()" to reverse the order of "vec_fac".
fac_vec <- NULL
How’d you do?
No code entered for vec_num yet.
No code entered for vec_int yet.
No code entered for vec_cha yet.
No code entered for vec_fac yet.
No code entered for vec_let yet.
No code entered for vec_ni yet.
No code entered for fac_vec yet.
c()
to combine vec_int
with
vec_fac
, what class of vector would you get?
Why?Answer:
new_vec <- c(TRUE, FALSE, TRUE, TRUE)
Answer:
# 1) Use matrix() to create a matrix with 10 rows and four columns filled with NA
mat_empty <- NULL
# 2) Assign "vec_num" to the first column of "mat_1" below.
mat_1 <- mat_empty # DO NOT EDIT THIS LINE; add code below it.
mat_1 <- NULL
# 3) Assign "vec_int" to the second column of "mat_2" below
mat_2 <- mat_1 # DO NOT EDIT THIS LINE; add code below it.
mat_2 <- NULL
# 4) Assign "vec_cha" and "vec_fac" to the third and fourth columns of "mat_3" using one assignment operator.
mat_3 <- mat_2 # DO NOT EDIT THIS LINE; add code below it.
mat_3 <- NULL
# 5) Select the fourth row from "mat_3" and assign it to the object "row_4" as a vector.
row_4 <- NULL
# 6) Assign the element in the 6th row and 2nd column of "mat_3" to "val_6_2" as a numeric value (using as.numeric).
val_6_2 <- NULL
# 7) Use "cbind()" to combine "vec_num", "vec_int", "vec_cha", and "vec_fac" into "mat_4".
mat_4 <- NULL
# 8) Next, first transpose mat_4, then select only the first four columns and assign to mat_t
mat_t <- NULL
# 9) Then use rbind() to add the rows from mat_3 to mat_t (mat_t first, mat_3 second) and assign this combination to mat_big.
mat_big <- NULL
How’d you do?
No code entered for mat_empty yet.
No code entered for mat_1 yet.
No code entered for mat_2 yet.
No code entered for mat_3 yet.
No code entered for row_4 yet.
No code entered for val_6_2 yet.
No code entered for mat_4 yet.
No code entered for mat_t yet.
No code entered for mat_big yet.
names()
from mat_4
? What about
colnames()
? What about rownames()
? Can you
guess why you get all these results?Answer:
mat_letters <- matrix(letters, ncol=2)
"a"
to "m"
in the
first column and "n"
to "z"
in the second.
What would be an easy way to make the matrix go in alphabetical order
left to right, top to bottom?Answer:
math_mat <- matrix(1:5, nrow=5, ncol=5)
math_vec <- 1:5
math_mat
and math_vec
. When you add
math_mat + math_vec
, what happens?math_mat %*% math_vec
and from
math_mat * math_vec
. Can you tell what is happening?Answer:
# 1) Use "list()" to create a list that contains "vec_num" and "row_4", and assign the names
# "vec_num" and "row_4" to these two elements of "list_1".
list_1 <- NULL
# 2) Using "$", extract "row_4" from "list_1" and assign it to the object "row_4_2".
row_4_2 <- NULL
# 3) Create another list that contains "val_6_2" and "mat_big".
list_2 <- NULL
# 4) Combine list_1 and list_2 together using "c()" and assign them to "list_3"
list_3 <- NULL
# 5) Use "unlist()" to turn "list_3" into a vector and assign it to "vector_3"
vector_3 <- NULL
# 6) Use "as.list()" to convert "vector_3" into a list and assign it to "list_big"
list_big <- NULL
# 7) Now copy "list_3" as "list_4" (one line of code). Then use "[[ ]]" to assign "list_3" as the last (fifth) element of "list_4";
# that is, you should have a list object with five elements named "list_4" that contains the same four
# elements as "list_3" plus a fifth element that is -all- four elements of "list_3" as one object.
list_4 <- NULL
# 8) Select the third element (that is, the sub-element) of the the fifth element of "list_4" and assign it
# to element_5_3 using "[[ ]]".
element_5_3 <- NULL
# 9) Lastly, repeat the previous assignment of the third element of the fifth element, but
# extract the element as a list rather than scalar using "[ ]" and assign it to "list_5_3".
list_5_3 <- NULL
How’d you do?
No code entered for list_1 yet.
No code entered for row_4_2 yet.
No code entered for list_2 yet.
No code entered for list_3 yet.
No code entered for vector_3 yet.
No code entered for list_big yet.
No code entered for list_4 yet.
No code entered for element_5_3 yet.
No code entered for list_5_3 yet.
Many functions in R produce lists as output because they produce
objects with different types of data and of different lengths. For
instance, consider the linear regression saved to lm.output
below. Don’t worry if you are not familiar with regression, we’re just
concerned with what the function produces!
lm.output <- lm(mpg ~ wt, data=mtcars)
lm.output
##
## Call:
## lm(formula = mpg ~ wt, data = mtcars)
##
## Coefficients:
## (Intercept) wt
## 37.285 -5.344
lm()
produce? Hint: use the function
length()
.Answer:
model
element?Answer:
coefficients
for the intercept
and
wt
? Remember to call on them from lm.output
object for your answer!Answer:
# 1) Use "data.frame()" to combine "vec_num" (first column) and "vec_int" (second column) into "df_1".
df_1 <- NULL
# 2) Use "$" to extract "vec_num" from "df_1", reverse it with "rev()", and assign it as the vector "vec_num_2".
vec_num_2 <- NULL
# 3) Use "$" to add "vec_num_2" to "df_2" as a new column with the name "number_vector".
df_2 <- df_1 # DO NOT EDIT THIS LINE; modify code below it.
df_2 <- NULL
# 4) Combine "df_2" with itself using "rbind()" to create "df_3"
df_3 <- NULL
How’d you do?
No code entered for df_1 yet.
No code entered for vec_num_2 yet.
No code entered for df_2 yet.
No code entered for df_3 yet.
names()
, colnames()
, and
rownames()
on df_1. How does this compare to the behavior
of these functions on lists and matrices?Answer:
length()
and
dim()
differ between data frames, lists, matrices, and
vectors?Answer: